\begin{align*} \int \frac{1}{(2x{2}+4x-2){-\frac{3}{2}}} \textrm{d}x &= \frac{\sqrt{2}}{8} \int\frac{\sec{t} \cdot \tan{t}}{\tan^{3}{t}} \textrm{d}t \\ &= \frac{\sqrt{2}}{8} \int\frac{\cos{t}}{\sin^{2}{t}} \textrm{d}t \end{align*}
Generally, \[\\mathsf{2}=2\]